Question

A voltmeter of resistance $998\Omega$ is connected across a cell of emf $2$V and internal resistance $2\Omega$. The potential difference across the voltmeter is?

• A. $1.99$V
• B. $3.5$V
• C. $5$V
• D. $6$V

Answer 1

The correct option is A $1.99$V

From Ohm's law
$i=\frac{E}{R+r}=\frac{2}{998+2}=2\times {10}^{-3}A$
Potential difference across the voltmeter is
$V=iR=(2\times {10}^{-3})\times 998$
$=1.996$V.