Question

Question 76

A wall of a room is of dimensions $5m\times 4m$. It has a window of dimensions $1.5m\times 1$ m and a door of dimensions $2.25m\times 1$ m. Find the area of the wall, which is to be painted.

Answer 1

Given, a wall of a room is of dimensions $5m\times 4m.$
$\therefore$ Length of the room = 5 m and breadth of the room = 4 m
$\therefore$ Area of the room $=l\times b=5\times 4=20m^2$
Also, length of the window = 1.5 m and breadth of the win dow = 1 m
$\therefore$ Area of the window $=l\times b=1.5\times 1=1.5m^2$
Now, length of the door = 2.25 m and breadth of the door = 1 m
\therefore Area of the door $=l\times b=2.25\times 1=2.25m^2$
Now, area of the wall to be painted = Area of the wall - (Area of the window + Area of the door) = 20 - (1.5 + 2.25) = 20 - 3.75$=16.25m^2$