A water pond appears to be 2.7 m deep. If the refractive index of water is 4/3, find the actual depth of the pond.

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Solution

Given,
Apparent depth = $2.7 m$
$μ_{w} = \frac{4}{3}$
Real depth = Apparent depth $* μ_{W}$
$= 2.7 \times \frac{4}{3} = 3.6 m$ .

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A water pond appears to be 2.7 m deep. If the refractive index of water is 4/3, find the actual depth of the pond.

Given,Apparent depth = 2.7mμw=43Real depth = Apparent depth ∗μW=2.7×43=3.6m.

Given,
Apparent depth = $2.7 m$
$μ_{w} = \frac{4}{3}$
Real depth = Apparent depth $* μ_{W}$
$= 2.7 \times \frac{4}{3} = 3.6 m$ .