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Question

A water sample has ppm level concentration of following anions
$$F^-=10;\,\,\, SO_4^{2-} = 100; \,\,\, NO_3^- = 50$$
The anion/anions that make/makes the water sample unsuitable for drinking is/are:


A
both SO24 and NO3
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B
only F
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C
only SO24
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D
only NO3
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Solution

The correct option is C only $$F^-$$
$$NO^{-3}$$ The maximum limit of nitrate $$NO^{-3}$$  in drinking water is 50 ppm and its source is fertilisers, lf the maximum limit is increased in water it will cause methemoglobinemia (blue baby syndrome) $$SO_4^{2-}$$. The maximum limit of sulphate ($$SO_4^{2-}$$ ) according to WHO is 500 pm and its sources are acid rain, industries. Excess $$SO_4^{2-}$$ has laxative effect. $$F^-$$  The maximum limit of fluoride ($$F^-$$) is about 1.5 ppm. lts higher concentration converts enamel to more harder fluorapatite. Concentration (> 2ppm) causes brown mottling of teeth and high concentration (> 10 ppm) are harmful for bones and teeth. $$SO_4^{2-}$$  (100 ppm) and $$NO^{-3}$$  (50 ppm) in water is suitable for drinking but the concentration of $$F^-$$ (10 ppm) makes water unsuitable for drinking.

Hence, the correct option is B.

Chemistry

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