Question

# A wave travelling along positive x-axis is given by $$=A\sin { \left( \omega t-kx \right) }$$. If it is reflected from a rigid boundary such that $$80$$% amplitude is reflected, then equation of reflected wave is

A
y=Asin(ωt+0.8kx)
B
y=0.8Asin(ωt+kx)
C
y=Asin(ωt+kx)
D
y=0.8Asin(ωt+kx)

Solution

## The correct option is C $$y=-0.8A\sin { \left( \omega t+kx \right) }$$On getting reflected from a rigid boundary the wave suffers an additional phase change of $$\pi$$.Hence, if $$\quad { y }_{ incident }=A\sin { \left( \omega t-kx \right) }$$Then, $${ y }_{ reflected }=(0.8A)\sin { \left( \omega t-k(-x)+\pi \right) } =-0.8A\sin { \left( \omega t+kx \right) }$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More