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Question

A weight lifter lifted a load of $$200kgf$$ to a height of $$2.5m$$ in $$5s$$. Take $$g=10N$$ $$kg^{-1}$$. Calculate the power developed by him.


A
10W
loader
B
1W
loader
C
1000W
loader
D
100W
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Solution

The correct option is C $$1000W$$
$$Work = F\times S\times \cos \theta $$.

Given mass = 200 Kgf and distance is 2.5 m and angle is 180 degree and we know that cos 180 = -1.

We know that $$F = m*g = 200*10 = 2000 N-f$$

Hence $$W = 2000*2.5 = 5000 Joule$$.

$$Power = work / time $$

$$ P = 5000/5 = 1000 \ Watt$$.

Physics

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