Question

A weight lifter lifted a load of $$200kgf$$ to a height of $$2.5m$$ in $$5s$$. Take $$g=10N$$ $$kg^{-1}$$. Calculate the power developed by him.

A
10W
B
1W
C
1000W
D
100W

Solution

The correct option is C $$1000W$$$$Work = F\times S\times \cos \theta$$.Given mass = 200 Kgf and distance is 2.5 m and angle is 180 degree and we know that cos 180 = -1.We know that $$F = m*g = 200*10 = 2000 N-f$$Hence $$W = 2000*2.5 = 5000 Joule$$.$$Power = work / time$$$$P = 5000/5 = 1000 \ Watt$$.Physics

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