A weightless spring which has a force constant $^{'} k^{'}$ oscillates with frequency $^{'} n^{'}$ when a mass $m$ is suspended from it. The spring is cut into two equal halves and a mass 2 $m$ is suspended from it. The frequency of oscillation will now become-

n

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2 n

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n / \sqrt{2}

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n (2)^{1 / 2}

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Solution

The correct option is A $n$

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The correct option is A $n$