A well is to be dug $20$ m deep, $2.25$ m inside diameter, with a brick lining of $0.35$ m thickness. Then the quantities of brickwork is

14.75 m^{3}

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57.2 m^{3}

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136.75 m^{3}

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572 m^{3}

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Solution

The correct option is A $57.2 m^{3}$
Volume of Brickwork $= π (r_{2}^{2} - r_{1}^{2}) h$
$r_{1}$ (Internal) $= \frac{2.25}{2} = 1.125 m$
$r_{2}$ (External) $= r_{1} + 0.35 = 1.475$
$h = 20 m$
$V = π (r_{2}^{2} - r_{1}^{2}) h$
$= π (0.91) \times 20$
$= 57.18 m^{3} \approx 57.2 m^{3}$

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20

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