Question

a well planned lokhandwala complex in Mumbai has two straight roads perpendicular to each other.There are 5 lanes parallel to road 1.Each lane has 8 houses.Srinivas lives in the 6th house of the 5th lane and Alok lives in the 2nd house of the 2nd lane .What will be the shortest distance between their house (take distance between each house as 1 unit).

Answer 1

This problem can easily be done by plotting the position of their houses into a co-ordinate plane. Srinivas lives in the 6th house of the 5th lane. This can be plotted to (6,5) Alok lives in the 2nd house of the 2nd lane. This can be plotted to (2,2) So, the distance can be found out by using distance formula ie, sqrt[ (x2 - x1)^2 + (y2 - y1)^2 ] = sqrt[ (6 - 2)^2 + (5 - 2)^2 ] = sqrt[ 16 + 9 ] = sqrt[ 25 ] = 5 units