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Question

Question 59 (a)

What should be added to x3+3x2y+3xy2+y3 to get x3+y3?

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Solution

In order to find the solution subtract x3+3x2y+3xy2+y3 from x3+y3.
Required expression is
x3+y3(x3+3x2y+3xy2+y3)=x3+y3x33x2y3xy2y3
On combining the like terms.
=x3x3+y3y33x2y3xy2=3x2y3xy2
So, if we add 3x2y3xy2 in x3+3x2y+3xy2+y3, we get x3+y3.


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