Question

# A wire can be broken by applying a load of 20 kg wt. The force required to break the wire of twicethe diameter is :

A
20 kg wt
B
5 kg wt
C
80 kg wt
D
160 kg wt.

Solution

## The correct option is C 80 kg wtBreaking stress is the characteristic of the material. Hence, for two wires of same material having different thickness$$\dfrac{F_1}{r_1^2} = \dfrac{F_2}{r_2^2}$$$$\dfrac{F_1}{r^2} = \dfrac{F_2}{(2r)^2}$$$$\dfrac{20}{r^2} = \dfrac{F_2}{(4r^2)}$$So, $$F_2 = 80 kg wt$$Physics

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