Question

A wire is cut into several small pieces. Each of the small pieces is bent into a square of side $2$ cm. If the total area of the small squares is $28$ square cm, what was the original length of the wire?

Answer 1

Find the area of each square

Given, the side of the square made by bending a small piece of wire$=2$ $cm$

The total area of the small squares made by bending small pieces of wire $=28$ $sq.$ $cm$

Now, the number of small squares $=$ $\frac{Totalareaofsmallsquares}{Areaofonesmallsquares}$

$=\frac{28}{2\times 2}=7$

Now, the perimeter of a small square $=4\times side$

$=4\times 2=8cm$

The perimeter of $7$such small squares $=$ Perimeter of one small square $\times 7$

$=8\times 7$

$=56$$cm$

∴ The original length of wire $=$ Perimeter of 7 small squares $=56$$cm$

Hence, the original length of wire is $56$$cm$