Question

A wire of $$10m$$ long and $$1mm$$$$^{2}$$ area of cross section is stretched by a force of $$20N$$. If the elongation is $$2mm$$, the young's modulus of the material of the wire (in pa) is

A
1 x 109
B
2 x 109
C
1 x 1011
D
1 x 1012

Solution

The correct option is D 1 x 10$$^{11}$$$$A=10^{-6} m^{2}$$$$0.002=\dfrac{10\times 20}{10^{-6}\times y}$$$$y=10^{11} N/m^{2}$$Physics

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