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Question

A wire of $$10m$$ long and $$1mm$$$$^{2}$$ area of cross section is stretched by a force of $$20N$$. If the elongation is $$2mm$$, the young's modulus of the material of the wire (in pa) is


A
1 x 109
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B
2 x 109
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C
1 x 1011
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D
1 x 1012
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Solution

The correct option is D 1 x 10$$^{11}$$
$$A=10^{-6} m^{2}$$
$$0.002=\dfrac{10\times 20}{10^{-6}\times y}$$
$$y=10^{11} N/m^{2}$$

Physics

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