CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A wire of density 9×103Kg/m3 is stretched between two clamps 1 m apart and is stretched to an extension of 4.9×104 meter, Young's modulus of material is 9×1010N/m2. Then

A
The lowest frequency of standing waveis 35 Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
The frequency of 1 st overtone is 70 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
The frequency of 1 st overtone iis 105 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
A and B both
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A The lowest frequency of standing waveis 35 Hz
This is a fundamental standing wave L=λ2λ=2L we know that, V=nλ Also Y=Tμ

n0=12LTμ Given, ρ=a×103 kg/m3l=1 mΔl=4.9×104 mY=9×1010 N/m2

n0=12×1VAΔllAρ=129×1010×4.9×1041×9×10310n0=35 Hz

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hooke's Law
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon