Question

A wire of length $\frac{11}{2}$ m is cut such that length of each piece is $\frac{22}{24}$ m. How many pieces required?

Answer 1

$\text{Length of the wire}=\frac{11}{2}$

$\text{Length of each piece of wire}=\frac{22}{24}$ m

$\text{Pieces required}=\frac{\text{Length of the wire}}{\text{Length of each piece}}$

$=\frac{11}{2}÷\frac{22}{24}$

$\Rightarrow \frac{11}{2}÷\frac{22}{24}=\frac{11}{2}\times \frac{24}{22}=\frac{11\times 24}{2\times 22}$

$\Rightarrow \frac{11\times 24}{2\times 22}=\frac{11\times 2\times 2\times 2\times 3}{2\times 2\times 11}=2\times 3=6$

Hence, length of each piece is 6 m.