A wire of length L and resistance R is elongated to length 2L.What is the value of new resistance?
A
2R
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B
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C
R
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D
4R
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Solution
The correct option is D 4R Volume (V) = L × A New length = 2L As Volume remains constant New Area = (L×A)2L = A2 R=ρLA Putting values, New resistance = 4R