Question

# A wire of resistance $$4 R$$ is bent in the form of a circle. What is the effective resistance between the ends of the diameter?

Solution

## When a wire of resistance $$4R$$ is bent in the form of circle, then the resistance of each segment across the diameter becomes $$2R$$ as shown in the figure.Equivalent resistance between A and B: $$\dfrac{1}{R_{AB}} = \dfrac{1}{R_1} + \dfrac{1}{R_B}$$            (in parallel combination)$$\therefore$$   $$\dfrac{1}{R_{AB}} = \dfrac{1}{2R} + \dfrac{1}{2R}$$ $$\dfrac{1}{R_{AB}} = \dfrac{2}{2R}$$                  $$\implies$$  $$R_{AB} =R$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More