A wire when bent in the form of an equilateral triangle encloses an area of 121√ cm2. The same wire is bent to form a circle. Find the area enclosed by the circle.
Area of an equilateral Δ=√4×a2 where a = side
Now, given that -
Therefore, length of wire = a + a + a = 66
Now, this wire is bent into a circle, so the circumference of the circle =2πr=66
Now, the area of this circle =πr2