A woman starts from her home at 9.00 am, walks with a speed of $5 k m h^{- 1}$ on a straight road up to her office 2.5 km away, stays at the office up to 5.00 pm, and returns home by an auto with a speed of $25 k m h^{- 1}$ . Plot the position-time graph of the woman taking her home as origin.

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Solution

Speed of the woman = $5 k m / h$
Distance between her office and home = $2.5$ km
Time taken = Distance / Speed
= 2.5 / 5 = 0.5 h = 30 min
It is given that she covers the same distance in the evening by an auto.
Now, speed of the auto = $25 k m / h$
Time taken = Distance / Speed
= $2.5 / 25 = 1 / 10 = 0.1 h = 6 m i n$
The suitable x-t graph of the motion of the woman is shown in the given figure.

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A woman starts from her home at 9.00 am, walks with a speed of 5kmh−1 on a straight road up to her office 2.5 km away, stays at the office up to 5.00 pm, and returns home by an auto with a speed of 25kmh−1. Plot the position-time graph of the woman taking her home as origin.

A woman starts from her home at 9.00 am, walks with a speed of $5 k m h^{- 1}$ on a straight road up to her office 2.5 km away, stays at the office up to 5.00 pm, and returns home by an auto with a speed of $25 k m h^{- 1}$ . Plot the position-time graph of the woman taking her home as origin.