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Question

A Woman weighing 50 kg stands on a weighting machine placed in a lift. What will be the reading of the machine, When the lift is (i) moving upwards with a uniform velocity of 5ms1 and (ii) moving downwards with a uniform acceleration of 1ms2? [Take g=10ms2].

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Solution



N+ma=mg where ma is the pseudo force.

N=m(ga)= weight read by machine

(a)a=0

N=mg=50×10=500N

(a)a=1

N=m(ga)=50×9=450N

1058484_1064050_ans_b3bb9b93411c42b0b5be7e6e9d2130ac.jpg

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