CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

a) Write the electronic configuration of Cu in s p d f

b) Which of the following orbitals has the lowest energy
4d, 4f, 5s, 5p

c) What is the wavelength of light emitted when the electrons in a hydrogen atom undergo the transition from an energy level n=4 to an energy level n=2?

Open in App
Solution

(a) Electronic configuration of Cu=1s22s22p63s23p63d104s1

(b)

4d n+1=4+2=6
4f n+1=4+3=7
5s n+1=5+0=5
5p n+1=5+1=6

So, 5s has the lowest energy.

(c)

1λ=RH(1h211h22)

1λ=RH(122142)

1λ=RH(14116)

λ=163RH

=163×91.6 Since, ( 1RH=91.6nm )

=488.5nm

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electronic Configuration and Orbital Diagrams
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon