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Question

a) x and y are I+ such that 2x5 and 3x+2y12. List all the possible values of y.

b) Solve the following inequation: x+215815,xϵR

[6 MARKS]

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Solution

Each subpart: 3 Marks

a) Given x=2,3,4,5 and 3x+2y12
Putting x = 2 in given inequation, we get
3×2+2y12
2y6
y3
So, y={1,2,3}

b)
x+215815,xϵR,15x+28 15x10 x23,xϵR




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