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Byju's Answer
Standard XII
Mathematics
Derivative from First Principle
ax=b, by=c, c...
Question
a
x
=
b
,
b
y
=
c
,
c
z
=
a
Find the value of x, y, z.
A
1
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B
N
o
t
v
a
l
i
d
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C
−
1
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D
0
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Solution
The correct option is
A
1
a
x
=
b
b
y
=
c
=
>
a
x
y
=
c
c
z
=
a
c
z
=
a
=
>
b
y
z
=
a
(
a
x
)
y
z
=
a
a
x
y
z
=
a
x
y
z
=
1
Suggest Corrections
0
Similar questions
Q.
If
x
=
b
y
+
c
z
+
d
u
,
y
=
c
z
+
a
x
+
d
u
,
z
=
a
x
+
b
y
+
d
u
,
u
=
a
x
+
b
y
+
c
z
.
Then the value of the expression.
a
1
+
a
+
b
1
+
b
+
c
1
+
c
+
d
1
+
d
is
Q.
If
a
x
y
+
b
y
x
=
c
,
b
y
z
+
c
z
y
=
a
,
c
z
x
+
a
x
z
=
b
,
then find the value of
y
z
x
2
+
z
x
y
2
+
x
y
z
2
Q.
a
,
b
,
c
are distinct real numbers, not equal to one. If
a
x
+
y
+
z
=
0
,
x
+
b
y
+
z
=
0
and
x
+
y
+
c
z
=
0
have a non-trivial solution, then the value of
1
1
−
a
+
1
1
−
b
+
1
1
−
c
is equal to
Q.
a
≠
b
≠
c
≠
1
;
a
x
+
y
+
z
=
0
,
x
+
b
y
+
z
=
0
,
x
+
y
+
cz
=
0
have non trivial solutions then
a
+
b
+
c
−
abc
=
…
…
…
…
…
Q.
If the system of equations
a
x
+
y
+
z
=
0
;
x
+
b
y
+
z
=
0
and
x
+
y
+
c
z
=
0
has a non-trivial solution, then the value of
1
1
−
a
+
1
1
−
b
+
1
1
−
c
is
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