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Question

AB and CD are two parallel lines. PQ cuts AB and CD at E and F respectively. EL is the bisector of FEB. If LEB=350, then CFQ will be 


Solution

AB || CD and PQ is the transversal EL is the bisector of FEB and LEB=350


FEB=2×350=700
AB||CD
FEB+EFD=1800
(Co-interior angles)
700+EFD=1800
EFD=1800700=1100
But CFQ=EFD
(Vertically opposite angles)
CFQ=1100

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