AB is a chord of the parabola y2=4ax with vertex at A. BC is drawn perpendicular to AB meeting the axis at C. the projection of BC on the x-axis is ka. What's the value of 'k'?
Here we are asked to find the projection of BC on the x-axis.
This is equal to the difference in the x coordinates of points B and C.
Lets first get the equation of BC
Slope of AB=2at−0at2−0=2t
∴ Equation of BC is,
for getting point C. solve BC with x-axis
∴ projection of BC on x-axis is =4a+at2−at2