Question

Question 2
ABC is a triangle, right angled at C. If AB = 25 cm and AC = 7 cm, find BC.

Answer 1

Given: AB = 25 cm, AC =7cm
Let BC be x cm.
In right angled triangle ACB,
$(Hypotenuse{)}^2=(Base{)}^2+(Perpendicular{)}^2$
[By Pythagoras theorem]

$\Rightarrow (AB{)}^2=(AC{)}^2+(BC{)}^2\Rightarrow (25{)}^2=(7{)}^2+x^2\Rightarrow 625=49+x^2\Rightarrow x^2=625-49=576x=\sqrt{576}=24cm$
Thus, the length of BC is 24cm