Question

# Question 4 ABC is an isosceles triangle right angled at C. Prove that AB2=2AC2.

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Solution

## Given that ΔABC is an isosceles triangle right angled at C. In ΔACB, ∠C=90∘ AC = BC (Given) ⇒ AB2=AC2+BC2 ([By using Pythagoras theorem] ⇒ AB2=AC2+AC2 [Since, AC = BC] ⇒ AB2=2AC2

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