△ABC is an isosceles triangle with AB=AC. Draw AP⊥BC to show that ∠B=∠C.
Showing that ∠B=∠C.
In ∆APB and ∆APC
∠APB=∠APC—————[ each 90°]
∴∆APB≅∆APC ———-[R.H.S congruence rule]
∠B=∠C —————[ by C.P.C.T]
Hence we proved that ∠B=∠C
ABC is an isosceles triangle with AB = AC. Drawn AP ⊥ BC to show that ∠B = ∠C.