ΔABC is isosceles with AB=AC=7.5cm and BC=9cm (Figure). The heightAD from A toBC, is 6cm. Find the area of ΔABC. What will be the height fromCto AB i.e., CE
Finding the area of ΔABC and height fromCto AB i.e., CE:
From the given figure we note that
We know that
Area of ΔABC=12×base×height
Area of △ABC,
Therefore the area of triangle △ABC=27cm2 and the height fromCto AB i.e., CE=7.2cm
ΔABC is an isosceles triangle with AB = AC = 13 cm. The length of altitude from A on BC is 5 cm. Find BC.