ABCD is a field in the shape of a trapezium. AB || DC and ∠ABC=90∘,∠DAB=60∘. Four sectors are formed with centers A, B, C, and D. The radius of each sector is 17.5 m. Find the total area of the four sectors
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Solution
Since AB||CD and ∠ ABC = 90∘. Therefore ∠ BCD = 90∘. Also,
∠BAD = 60∘
∴∠CDA=180∘−60∘=120∘
We have, Total area of the four sectors
= Area of sector at A + Area of sector at B + Area of sector at C + Area of sector at D.