ABCD is a parallelogram. O is an interior point. If ar $(A O B) + a r (D O C) = 43$ sq units, then ar(|| $^{g m}$ ABCD) is :

172 sq units

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176 sq units

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43 sq units

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86 sq units

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Solution

The correct option is B 86 sq units
Ar (AOB) = $\frac{1}{2} (A B) (h)$

Ar (DOC) = $\frac{1}{2} (C D) (h^{'})$

Ar(AOB) + Ar(DOC) = $\frac{1}{2} (A B) (h + h^{'})$ [ AB = CD ]

43 = $\frac{1}{2}$ (AB) (height) = $\frac{1}{2}$ (Area of parallelogram ABCD )

Hence, Ar (ABCD) = 86

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ABCD is a parallelogram. O is an interior point. If ar(AOB)+ar(DOC)=43 sq units, then ar(||gm ABCD) is :

The correct option is B 86 sq unitsAr (AOB) = 12(AB)(h)Ar (DOC) = 12(CD)(h′)Ar(AOB) + Ar(DOC) = 12(AB)(h+h′) [ AB = CD ] 43 = 12 (AB) (height) = 12 (Area of parallelogram ABCD ) Hence, Ar (ABCD) = 86

ABCD is a parallelogram. O is an interior point. If ar $(A O B) + a r (D O C) = 43$ sq units, then ar(|| $^{g m}$ ABCD) is :

The correct option is B 86 sq units
Ar (AOB) = $\frac{1}{2} (A B) (h)$

Ar (DOC) = $\frac{1}{2} (C D) (h^{'})$

Ar(AOB) + Ar(DOC) = $\frac{1}{2} (A B) (h + h^{'})$ [ AB = CD ]

43 = $\frac{1}{2}$ (AB) (height) = $\frac{1}{2}$ (Area of parallelogram ABCD )

Hence, Ar (ABCD) = 86