Question

ABCD is a parallelogram with sides $AB=12cm$, $BC=10cm$ and diagonal $AC=16cm$. Find the approximate area of the parallelogram.

• A. $119.8c{m}^2$
• B. $103.7c{m}^2$
• C. $15.7c{m}^2$
• D. None of these

Answer 1

The correct option is A $119.8c{m}^2$

Area of triangle with sides $12cm,10cm,16cm$:

$s=\frac{12+10+16}{2}=19$

Area, A = $\sqrt{s(s-a)(s-b)(s-c)}$

$A=\sqrt{19(19-12)(19-10)(19-16)}$

$A=59.9$ sq. cm

Therefore,

Area of parallelogram $=2A=2\times 59.9=119.8$ sq. cm