CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

ABCD is a quadrilateral such that DAAB and CBAB, x = y and EF || AD such that EF bisects DEC. Then CD2


A
2CE2
loader
B
2AE2
loader
C
2CB2
loader
D
2AB2
loader

Solution

The correct option is A 2CE2
Given,
ABCD is a quadrilateral with DAAB and CBAB
and EF || AD
EF||BC
EFAB
Now, in ΔDAE and ΔCBE,
DAE=CBE   [each 90]
Also, DEA=CEB
ΔDAEΔCBE   [by AA similarity]
DEAE=CEBEDE=CE    ...(i)
Now, in ΔDEC, right angled at E,
DE2+CE2=DC22DE2=2CE2=DC2

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More



footer-image