Question

ABCD is a square where each each side is a uniform wire of resistance $1\Omega$. A point E lies on CD such that is a uniform wire of resistance $1\Omega$ is connected across AE and constant potential difference is applied across A and C , then B and E are equipotential.

• A. $\frac{CE}{ED}=1$
• B. $\frac{CE}{ED}=\frac{1}{\sqrt{2}}$
• C. $\frac{CE}{ED}=\frac{1}{2}$
• D. $\frac{CE}{ED}=\frac{\sqrt{2}}{1}$

Answer 1

Answer: (D)

$\frac{CE}{ED}=\frac{\sqrt{2}}{1}$

Wire of resistance $=1\Omega$

Keeping in view that, $ABCD$ is a square where each side is uniform wire of resistance $1\Omega$. If a uniform wire of resistance $1\Omega$ is connected across $AE$ and a potential difference is applied across $A$ and $C$, the points $B$ and $E$ will be equipotential; a point $E$ on $CD$ is $\frac{CE}{ED}=\frac{\sqrt{2}}{1}$

$\therefore$ $CE:ED=\sqrt{2}:1$