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Question

ABCD is a trapezium in which AB || CD and AD = BC (see the given figure). From the figure, which of the following can be deduced?


A
ΔABCΔBCD
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B
ΔABCΔBCE
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C
ΔABCΔBAD
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D
None of these
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Solution

The correct option is C ΔABCΔBAD
In ΔABC and  ΔABD,
AB = BA  (Common side)
BC = AD  (Given)
B=A (Proved before)
ΔABCΔBAD (SAS congruence rule)

Mathematics

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