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Question

ABCD is a trapezium in which AB ⃦CD and AD =BC (see the given figure). Show that
(i) ∠A = ∠B
(ii) ∠C=∠D
(iii) △ABC ≅△BAD
(iv) Diagonal AC=diagonal BD
[Hint: Extend AB and draw a line through C parallel to DA intersecting AB produced at E.]


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