ABCD is a trapezium with AB - CD- Find the value of -BAD if - ADC - 60-o- 100- nbsp-120- nbsp-60- nbsp-80- nbsp-

The correct option is B 120° nbsp;ABCD is a trapezium and AB || CD. ∠ ADC = 60^∘ (Given) ∠ ADC + ∠ BAD = 180^∘ (AB || CD and AD is the transversal. Hence, s ...

ABCD is a tra...

Question

ABCD is a trapezium with AB || CD. Find the value of $∠$ BAD if $∠ A D C = 60^{o}$ .

60°

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80°

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100°

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120°

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Solution

The correct option is B 120°
ABCD is a trapezium and AB || CD.

$∠ A D C = 60^{\circ} (G i v e n)$
$∠ A D C + ∠ B A D = 180^{\circ}$
(AB || CD and AD is the transversal. Hence, sum of co-interior angles are supplementary)

$\Rightarrow 60^{\circ} + ∠ B A D = 180^{\circ}$
$\Rightarrow ∠ B A D = 180^{\circ} - 60^{\circ} = 120^{\circ}$

Thus,
$∠ B A D = 120^{\circ}$

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ABCD is a trapezium with AB || CD. Find the value of ∠BAD if ∠ADC=60o.

The correct option is B 120° ABCD is a trapezium and AB || CD. ∠ADC=60∘ (Given) ∠ADC+∠BAD=180∘ (AB || CD and AD is the transversal. Hence, sum of co-interior angles are supplementary) ⇒60∘+∠BAD=180∘ ⇒∠BAD=180∘−60∘=120∘ Thus, ∠BAD=120∘

ABCD is a trapezium with AB || CD. Find the value of $∠$ BAD if $∠ A D C = 60^{o}$ .