Question

According the Bohr principle, the relation between principle quantum number (n) and radius of orbit is:
r ∝ n
r ∝ 1/n
r ∝ 1/n^2
r ∝ n^2

Answer 1

Dear Student,

$$\begin{gathered} Weknow, \\ Bohr\text{'}sradius=\frac{n^2{h}^2}{4{\pi }^{2}km{e}^{4}z} \\ Wecansee,r\propto n^2 \end{gathered}$$

Regards,