Question

# According to Bohr's theory, the angular momentum of an electron in $$5^{th}$$ orbit is:

A
2.5h/π
B
25h/π
C
1.0h/π
D
10h/π

Solution

## The correct option is A $$2.5h/\pi$$Expression for angular momentum is written as, $$L = \dfrac {nh}{2\pi}$$.For $$5^{th}$$ orbit $$, n= 5$$.$$L = \dfrac {5h}{2\pi}= \dfrac {2.5h}{\pi}$$Hence, option A is correct.Chemistry

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