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Question

According to Bohr's theory, the angular momentum of an electron in $$5^{th}$$ orbit is:


A
2.5h/π
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B
25h/π
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C
1.0h/π
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D
10h/π
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Solution

The correct option is A $$2.5h/\pi $$
Expression for angular momentum is written as, $$ L = \dfrac {nh}{2\pi}$$.

For $$5^{th}$$ orbit $$, n= 5$$.

$$ L = \dfrac {5h}{2\pi}= \dfrac {2.5h}{\pi} $$

Hence, option A is correct.

Chemistry

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