According to Charles-s law- V1T1 -

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Temperature-Volume Relationship

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Question

According to Charles's law, $\frac{V_{1}}{T_{1}} =$ :

\frac{V_{2}}{T_{2}}

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\frac{T_{2}}{V_{2}}

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V_{2} \times T_{2}

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none of these

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Solution

The correct option is A $\frac{V_{2}}{T_{2}}$
According to charle's law, at constant pressure, volume of a gas is directly proportional to temperature.
$V \propto T V = K T, K = constant$ (at constant pressure)
$V_{1} = K T_{1} V_{2} = K T_{2} ⟹ K = \frac{V_{2}}{T_{2}} V_{1} = \frac{V_{2}}{T_{2}} T_{1} \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

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According to Charles's law, V1T1=:

The correct option is A V2T2According to charle's law, at constant pressure, volume of a gas is directly proportional to temperature.V∝TV=KT,K= constant (at constant pressure)V1=KT1V2=KT2⟹K=V2T2V1=V2T2T1V1T1=V2T2

According to Charles's law, $\frac{V_{1}}{T_{1}} =$ :