Question

# According to Charles's law:V∝1T(dVdT)P=K(1T−VT2)=0None of these

Solution

## The correct option is B (dVdT)P=KFrom the ideal gas equation, PV=nRT V=nRTP at constant pressure and number of moles V=KT Upon differentiating, (dV=KdT)P (dVdT)P=K This is the differential form of Charle's law.

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