According to Graham's Law, the rate of diffusion of $C O, O_{2}, N_{2}$ and $C O_{2}$ follows the order.

C O = N_{2} > O_{2} > C O_{2}

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C O = N_{2} > C O_{2} > O_{2}

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O_{2} > C O = N_{2} > C O_{2}

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C O_{2} > O_{2} > C O = N_{2}

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Solution

The correct option is A $C O = N_{2} > O_{2} > C O_{2}$
According to Graham's law of diffusion:
$R a t e o f d i f f u s i o n, R \propto \sqrt{\frac{1}{M}}$
Calculating molecular mass ( $M$ ) as:
$C O$ =28 g/ mol
$N_{2}$ =28 g/ mol
$O_{2}$ =32 g/ mol
$C O_{2}$ =44 g/ mol
Order of molecular wt: $C O = N_{2} < O_{2} < C O_{2}$
therefore order of rate of diffusion will be opposite to tha of molecular mass:
$C O = N_{2} > O_{2} > C O_{2}$
Option A is correct.

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