Question

# According to molecular orbital theory, which of the following will not be a viable molecule?

A
H2
B
H22
C
He2+2
D
He+2

Solution

## The correct option is B $$H_2^{2-}$$Electronic configuration of $$H_2 {^{2-}} = (\sigma 1s^2)(\sigma ^*1 s^2)$$Bond order of $$H_2^{2\circleddash} = \dfrac{N_b-N_a}{2} = \dfrac{2-2}{2} = 0$$.If a bond order of zero is obtained, that means that the molecule is too unstable and so it will not exist.Hence, $$H_2^{2\circleddash}$$ does not exit, due to zero bond order.Option B is correct. Chemistry

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