Question

According to Pauling electronegativity scale, the percentage ionic character in A - B molecule may be given as:
Percent ionic character $=18(X_B-X_A{)}^{1.4}$,
where $X_B$ and $X_A$ are electronegativities of B and A, respectively and $X_B>X_A.$ If $X_A=1.84X_B=3.48,$ then the percentage ionic character in A - B is: (Given: $(1.64{)}^{7/5}=2.0)$

Answer 1

Percent ionic character $=18(X_B-X_A{)}^{1.4}$
$=18(3.48-1.84{)}^{1.4}$
$=18(1.64{)}^{1.4}$
using $(1.64{)}^{7/5}=2.0$
$=18\times 2=36\%$