Question

According to the Bohr Theory, which of the following transactions in the hydrogen atom will give rise to the least energetic photon ?

• A. $n=6$ to $n=1$
• B. $n=5$ to $n=4$
• C. $n=6$ to $n=5$
• D. $n=5$ to $n=3$

Answer 1

The correct option is C $n=6$ to $n=5$

Energy levels are inverse proportion to the square of n. Therefore the least energetic photon would be when the difference between the energy levels is least. This would be when the difference is only 1 level of n. Higher the n, lower the energy. Thus the energy from 6 to 5 would be the least.