CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

According to the Bohr Theory, which of the following transitions in the hydrogen atom will give rise to the least energetic photon?


A
n=5 to n=3
loader
B
n=6 to n=1
loader
C
n=5 to n=4
loader
D
n=6 to n=5
loader

Solution

The correct option is C $$n = 6$$ to $$n = 5$$
$$E=-13.6\cfrac { { z }^{ 2 } }{ { n }^{ 2 } } eV$$. 

Thus $$E\propto \cfrac { 1 }{ { n }^{ 2 } } $$.

For the transition $$n_2 \rightarrow n_1$$ we have,
$$\Delta E \propto (\dfrac{1}{n_1^2}- \dfrac{1}{n_2^2})$$
 If we observe this relationship closely, we can observe more higher value of n, more less the value of E. Thus least energetic photon is observed in transition of $$n=6$$ to $$n=5$$. Thus answer is option D.

Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image