Account for t...

Question

Account for the following:
Iron on reaction with $H C l$ forms $F e C l_{2}$ and not $F e C l_{3}$ .

Open in App

Solution

Iron reacts with $H C l$ to form $F e C l_{2}$ and $H_{2}$

$F e + 2 H C l \to F e C l_{2} + H_{2}$

$H_{2}$ thus produced prevents the oxidation of $F e C l_{2}$ to $F e C l_{3}$ .

Suggest Corrections

Similar questions

P {C l}_{5}

P {C l}_{3}

H C l

F e {C l}_{2}

F e {C l}_{3}

O - O

H C l

F e C l_{2}

F e C l_{3}

(i) F e C l_{2} + H_{2} O_{2} + H C l \to F e C l_{3} + H_{2} O

F e C l_{3}

F e C l_{2}

S n C l_{2}

S n

S n^{4 +}

S n^{2 +}

F e C l_{3}

S n

H C l

F e C l_{3}

F e C l_{2}

F e C l_{3} + H_{2} S \to F e C l_{2} + H C l + S