Acetamide is treated separately with following reagents. Which one of these would give methylamine?

P {C l}_{5}

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Sodalime

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N a O H + {B r}_{2}

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H_{2} {S O}_{4}

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Solution

The correct option is D $N a O H + {B r}_{2}$
When acetamide is treated with bromine and NaOH, methyl amine is obtained.
The reaction is Hoffmann bromamide degradation reaction in which an amide is converted to an amine containing one carbon atom less.
$C H_{3} C O N H_{2} + B r_{2} + 4 N a O H \to C H_{3} N H_{2} + 2 K B r + N a_{2} C O_{3} + 2 H_{2} O$

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If acetamide is treated with the following reagents separately, which one of these would yield methylamine?

Acetamide is treated separately with the following reagents. Which would give methyl amine

[IIT 1983; CPMT 1988, 94; MP PET 1993;

MP PMT 1996; AIIMS 1998]

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