Acetamide on treatment with $L i A l H_{4}$ forms:

ethyl amine

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ethanoic acid

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ethanimine

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none of these

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Solution

The correct option is A ethyl amine
Acetamide on treatment with $L i A l H_{4}$ forms ethyl amine.
$C H_{3} C O N H_{2} (1) L i A l H_{4} / d i e t h y l e t h e r - -------------- \to (2) H_{3} O^{+} C H_{3} C H_{2} - N H_{2}$
Lithium aluminium hydride reduces amide group to form corresponding amine.

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