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Question

Add: (4x27xy+4y23),(5+6y28xy+x2) and (62xy+2x25y2).

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Solution

Let us add the given expressions 4x27xy+4y23,5+6y28xy+x2 and 62xy+2x25y2 as shown below:

(4x27xy+4y23)+(5+6y28xy+x2)+(62xy+2x25y2)=4x27xy+4y23+5+6y28xy+x2+62xy+2x25y2=(4x2+x2+2x2)+(7xy8xy2xy)+(4y2+6y25y2)+(3+5+6)(Combiningliketerms)=(4+1+2)x2+(782)xy+(4+65)y2+8=7x217xy+5y2+8

Hence, (4x27xy+4y23)+(5+6y28xy+x2)+(62xy+2x25y2)=7x217xy+5y2+8.

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